SQLite PHP

SQLite3 擴展在PHP 5.3.0是默認啟用。這也可能它通過使用禁用 --without-sqlite3 在編譯的時候。

Windows用戶必須啟用php_sqlite3.dll為了使用這個擴展。這個DLL包含與Windows分派PHP 如 PHP 5.3.0。

有關詳細的安裝說明，請查看我們的PHP教學和其官方網站上。

PHP 接口API

以下是重要的PHP程序，就足夠完成工作要求從PHP程序使用SQLite數據庫。如果要找一個更複雜的應用程序，那麼你可以看看到PHP官方文件。

S.N.	API & 描述
1	public void SQLite3::open ( filename, flags, encryption_key ) 打開一個SQLite3數據庫。如果構建包括加密，然後它會試圖使用密鑰。 If the filename is given as ':memory:', SQLite3::open() will create an in-memory database in RAM that lasts only for the duration of the session. If filename is actual device file name, SQLite3::open() attempts to open the database file by using its value. If no file by that name exists then a new database file by that name gets created. Optional flags used to determine how to open the SQLite database. By default, open uses SQLITE3_OPEN_READWRITE \| SQLITE3_OPEN_CREATE.
2	public bool SQLite3::exec ( string $query ) This routine provides a quick, easy way to execute SQL commands provided by sql argument which can consist of more than one SQL command. This routine is used to execute a result-less query against a given database.
3	public SQLite3Result SQLite3::query ( string $query ) This routine executes an SQL query, returning an SQLite3Result object if the query returns results.
4	public int SQLite3::lastErrorCode ( void ) This routine returns the numeric result code of the most recent failed SQLite request
5	public string SQLite3::lastErrorMsg ( void ) This routine returns english text describing the most recent failed SQLite request.
6	public int SQLite3::changes ( void ) This routine returns the number of database rows that were updated or inserted or deleted by the most recent SQL statement
7	public bool SQLite3::close ( void ) This routine closes a database connection previously opened by a call to SQLite3::open().
8	public string SQLite3::escapeString ( string $value ) This routine returns a string that has been properly escaped for safe inclusion in an SQL statement.

連接到數據庫

下麵的PHP代碼顯示了如何連接到一個現有的數據庫。如果數據庫不存在，那麼它就會被創建，終於將返回一個數據庫對象。

<?php
   class MyDB extends SQLite3
   {
      function __construct()
      {
         $this->open('test.db');
      }
   }
   $db = new MyDB();
   if(!$db){
      echo $db->lastErrorMsg();
   } else {
      echo "Opened database successfully
";
   }
?>

現在，讓我們運行上麵的程序在當前目錄中創建我們的數據庫test.db。按要求可以改變你的路徑。如果數據庫創建成功，則它會給下麵的消息：

Open database successfully

創建表

下麵的PHP程序將使用以前創建的數據庫中創建一個表：

<?php
   class MyDB extends SQLite3
   {
      function __construct()
      {
         $this->open('test.db');
      }
   }
   $db = new MyDB();
   if(!$db){
      echo $db->lastErrorMsg();
   } else {
      echo "Opened database successfully
";
   }

   $sql =<<<EOF
      CREATE TABLE COMPANY
      (ID INT PRIMARY KEY     NOT NULL,
      NAME           TEXT    NOT NULL,
      AGE            INT     NOT NULL,
      ADDRESS        CHAR(50),
      SALARY         REAL);
EOF;

   $ret = $db->exec($sql);
   if(!$ret){
      echo $db->lastErrorMsg();
   } else {
      echo "Table created successfully
";
   }
   $db->close();
?>

上述程序執行時，它會創建表COMPANYtest.db的，它會顯示以下消息：

Opened database successfully
Table created successfully

INSERT 操作

PHP程序，顯示我們如何能夠創造我們的COMPANY在上麵的例子中創建表中的記錄：

<?php
   class MyDB extends SQLite3
   {
      function __construct()
      {
         $this->open('test.db');
      }
   }
   $db = new MyDB();
   if(!$db){
      echo $db->lastErrorMsg();
   } else {
      echo "Opened database successfully
";
   }

   $sql =<<<EOF
      INSERT INTO COMPANY (ID,NAME,AGE,ADDRESS,SALARY)
      VALUES (1, 'Paul', 32, 'California', 20000.00 );

      INSERT INTO COMPANY (ID,NAME,AGE,ADDRESS,SALARY)
      VALUES (2, 'Allen', 25, 'Texas', 15000.00 );

      INSERT INTO COMPANY (ID,NAME,AGE,ADDRESS,SALARY)
      VALUES (3, 'Teddy', 23, 'Norway', 20000.00 );

      INSERT INTO COMPANY (ID,NAME,AGE,ADDRESS,SALARY)
      VALUES (4, 'Mark', 25, 'Rich-Mond ', 65000.00 );
EOF;

   $ret = $db->exec($sql);
   if(!$ret){
      echo $db->lastErrorMsg();
   } else {
      echo "Records created successfully
";
   }
   $db->close();
?>

上述程序執行時，它會創建COMPANY表中的記錄，並顯示以下兩行：

Opened database successfully
Records created successfully

SELECT 操作

PHP程序表明我們如何能夠獲取並顯示COMPANY 表在上麵的例子中創建表的記錄：

<?php
   class MyDB extends SQLite3
   {
      function __construct()
      {
         $this->open('test.db');
      }
   }
   $db = new MyDB();
   if(!$db){
      echo $db->lastErrorMsg();
   } else {
      echo "Opened database successfully
";
   }

   $sql =<<<EOF
      SELECT * from COMPANY;
EOF;

   $ret = $db->query($sql);
   while($row = $ret->fetchArray(SQLITE3_ASSOC) ){
      echo "ID = ". $row['ID'] . "
";
      echo "NAME = ". $row['NAME'] ."
";
      echo "ADDRESS = ". $row['ADDRESS'] ."
";
      echo "SALARY =  ".$row['SALARY'] ."

";
   }
   echo "Operation done successfully
";
   $db->close();
?>

當上述程序執行時，它會產生以下結果：

Opened database successfully
ID = 1
NAME = Paul
ADDRESS = California
SALARY =  20000

ID = 2
NAME = Allen
ADDRESS = Texas
SALARY =  15000

ID = 3
NAME = Teddy
ADDRESS = Norway
SALARY =  20000

ID = 4
NAME = Mark
ADDRESS = Rich-Mond
SALARY =  65000

Operation done successfully

UPDATE 操作

下麵的PHP代碼顯示了如何我們可以使用UPDATE語句來更新任何記錄，然後獲取並顯示更新的記錄，從COMPANY 表：

<?php
   class MyDB extends SQLite3
   {
      function __construct()
      {
         $this->open('test.db');
      }
   }
   $db = new MyDB();
   if(!$db){
      echo $db->lastErrorMsg();
   } else {
      echo "Opened database successfully
";
   }
   $sql =<<<EOF
      UPDATE COMPANY set SALARY = 25000.00 where ID=1;
EOF;
   $ret = $db->exec($sql);
   if(!$ret){
      echo $db->lastErrorMsg();
   } else {
      echo $db->changes(), " Record updated successfully
";
   }

   $sql =<<<EOF
      SELECT * from COMPANY;
EOF;
   $ret = $db->query($sql);
   while($row = $ret->fetchArray(SQLITE3_ASSOC) ){
      echo "ID = ". $row['ID'] . "
";
      echo "NAME = ". $row['NAME'] ."
";
      echo "ADDRESS = ". $row['ADDRESS'] ."
";
      echo "SALARY =  ".$row['SALARY'] ."

";
   }
   echo "Operation done successfully
";
   $db->close();
?>

當上述程序執行時，它會產生以下結果：

Opened database successfully
1 Record updated successfully
ID = 1
NAME = Paul
ADDRESS = California
SALARY =  25000

ID = 2
NAME = Allen
ADDRESS = Texas
SALARY =  15000

ID = 3
NAME = Teddy
ADDRESS = Norway
SALARY =  20000

ID = 4
NAME = Mark
ADDRESS = Rich-Mond
SALARY =  65000

Operation done successfully

DELETE 操作

下麵的PHP代碼，表明我們如何能夠使用DELETE語句刪除任何記錄，然後獲取並顯示剩餘的記錄COMPANY 表：

<?php
   class MyDB extends SQLite3
   {
      function __construct()
      {
         $this->open('test.db');
      }
   }
   $db = new MyDB();
   if(!$db){
      echo $db->lastErrorMsg();
   } else {
      echo "Opened database successfully
";
   }
   $sql =<<<EOF
      DELETE from COMPANY where ID=2;
EOF;
   $ret = $db->exec($sql);
   if(!$ret){
     echo $db->lastErrorMsg();
   } else {
      echo $db->changes(), " Record deleted successfully
";
   }

   $sql =<<<EOF
      SELECT * from COMPANY;
EOF;
   $ret = $db->query($sql);
   while($row = $ret->fetchArray(SQLITE3_ASSOC) ){
      echo "ID = ". $row['ID'] . "
";
      echo "NAME = ". $row['NAME'] ."
";
      echo "ADDRESS = ". $row['ADDRESS'] ."
";
      echo "SALARY =  ".$row['SALARY'] ."

";
   }
   echo "Operation done successfully
";
   $db->close();
?>

當上述程序執行時，它會產生以下結果：

Opened database successfully
1 Record deleted successfully
ID = 1
NAME = Paul
ADDRESS = California
SALARY =  25000

ID = 3
NAME = Teddy
ADDRESS = Norway
SALARY =  20000

ID = 4
NAME = Mark
ADDRESS = Rich-Mond
SALARY =  65000

Operation done successfully