Java XPath解析器 - 解析XML文檔
使用XPath的步驟
以下是使用XPath解析器在解析文檔時使用的步驟。
-
導入XML相關的軟件包。
-
創建DocumentBuilder
-
從文件或數據流創建一個文檔
-
創建XPath對象和XPath的路徑表達式
-
編譯XPath表達式使用XPath.compile() ,並由XPath.evaluate()評估計算獲得一個節點列表
-
遍曆節點列表。
-
檢查屬性
-
檢查子元素
導入XML相關的軟件包
import org.w3c.dom.*; import org.xml.sax.*; import javax.xml.parsers.*; import javax.xml.xpath.*; import java.io.*;
創建DocumentBuilder
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); DocumentBuilder builder = factory.newDocumentBuilder();
從文件或數據流創建一個文檔
StringBuilder xmlStringBuilder = new StringBuilder(); xmlStringBuilder.append("<?xml version="1.0"?> <class> </class>"); ByteArrayInputStream input = new ByteArrayInputStream( xmlStringBuilder.toString().getBytes("UTF-8")); Document doc = builder.parse(input);
構建XPath
XPath xPath = XPathFactory.newInstance().newXPath();
準備路徑表達式,並計算它
String expression = "/class/student"; NodeList nodeList = (NodeList) xPath.compile(expression).evaluate(doc, XPathConstants.NODESET);
遍曆節點列表
for (int i = 0; i < nodeList.getLength(); i++) { Node nNode = nodeList.item(i); ... }
檢查屬性
//returns specific attribute getAttribute("attributeName"); //returns a Map (table) of names/values getAttributes();
檢查子元素
//returns a list of subelements of specified name getElementsByTagName("subelementName"); //returns a list of all child nodes getChildNodes();
演示示例:
這裡是我們需要分析輸入文本文件:
<?xml version="1.0"?> <class> <student rollno="393"> <firstname>dinkar</firstname> <lastname>kad</lastname> <nickname>dinkar</nickname> <marks>85</marks> </student> <student rollno="493"> <firstname>Vaneet</firstname> <lastname>Gupta</lastname> <nickname>vinni</nickname> <marks>95</marks> </student> <student rollno="593"> <firstname>jasvir</firstname> <lastname>singh</lastname> <nickname>jazz</nickname> <marks>90</marks> </student> </class>
演示示例:
XPathParserDemo.java
package com.yiibai.xml; import java.io.File; import java.io.IOException; import javax.xml.parsers.DocumentBuilderFactory; import javax.xml.parsers.DocumentBuilder; import javax.xml.parsers.ParserConfigurationException; import javax.xml.xpath.XPath; import javax.xml.xpath.XPathConstants; import javax.xml.xpath.XPathExpressionException; import javax.xml.xpath.XPathFactory; import org.w3c.dom.Document; import org.w3c.dom.NodeList; import org.w3c.dom.Node; import org.w3c.dom.Element; import org.xml.sax.SAXException; public class XPathParserDemo { public static void main(String[] args) { try { File inputFile = new File("input.txt"); DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance(); DocumentBuilder dBuilder; dBuilder = dbFactory.newDocumentBuilder(); Document doc = dBuilder.parse(inputFile); doc.getDocumentElement().normalize(); XPath xPath = XPathFactory.newInstance().newXPath(); String expression = "/class/student"; NodeList nodeList = (NodeList) xPath.compile(expression).evaluate(doc, XPathConstants.NODESET); for (int i = 0; i < nodeList.getLength(); i++) { Node nNode = nodeList.item(i); System.out.println("\nCurrent Element :" + nNode.getNodeName()); if (nNode.getNodeType() == Node.ELEMENT_NODE) { Element eElement = (Element) nNode; System.out.println("Student roll no : " + eElement.getAttribute("rollno")); System.out.println("First Name : " + eElement .getElementsByTagName("firstname") .item(0) .getTextContent()); System.out.println("Last Name : " + eElement .getElementsByTagName("lastname") .item(0) .getTextContent()); System.out.println("Nick Name : " + eElement .getElementsByTagName("nickname") .item(0) .getTextContent()); System.out.println("Marks : " + eElement .getElementsByTagName("marks") .item(0) .getTextContent()); } } } catch (ParserConfigurationException e) { e.printStackTrace(); } catch (SAXException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } catch (XPathExpressionException e) { e.printStackTrace(); } } }
這將產生以下結果:
Current Element :student Student roll no : 393 First Name : dinkar Last Name : kad Nick Name : dinkar Marks : 85 Current Element :student Student roll no : 493 First Name : Vaneet Last Name : Gupta Nick Name : vinni Marks : 95 Current Element :student Student roll no : 593 First Name : jasvir Last Name : singh Nick Name : jazz Marks : 90