removeRange(int fromIndex,int toIndex) 方法用於刪除列表索引fromIndex(包括)和為toIndex(不包括)之間的所有元素。

聲明

以下是java.util.Vector.removeRange()方法的聲明

protected void removeRange(int fromIndex,int toIndex)

參數

• fromIndex --這是要移除的第一個元素的索引。

• toIndex --這是要去除最後一個元素之後的索引

返回值

NA

異常

• NA

例子

下麵的例子顯示java.util.Vector.removeRange()方法的使用。

package com.yiibai;

import java.util.Vector;

public class VectorDemo {
   public static void main(String[] args) {
      // create an empty Vector vec with an initial capacity of 7      
      Vector vec = new Vector(7);

      // use add() method to add elements in the vector
      vec.add(1);
      vec.add(2);
      vec.add(3);
      vec.add(4);
      vec.add(5);
      vec.add(6);
      vec.add(7);

      /**
       * Removing range of elements is not directly supported. However, it
       * can be done by using subList and clear methods.
      */
      System.out.println("Remove elements from 2nd to 4th");
      vec.subList(2,4).clear();
      
      // let us print all the elements available in vector
      System.out.println("Numbers after removal :- "); 
      for (Integer number : vec) {         
         System.out.println("Number = " + number);
      }           
   }    
} 

現在編譯和運行上麵的代碼示例，將產生以下結果。

Remove elements from 2nd to 4th
Numbers after removal :- 
Number = 1
Number = 2
Number = 5
Number = 6
Number = 7