java.util.Scanner.nextDouble()方法實例
java.util.Scanner.nextDouble() 方法掃描輸入的下一個標記為double。此方法將拋出InputMismatchException如果下一個標記不能轉換為有效的double值。如果轉換成功,則scanner執行匹配的輸入。
聲明
以下是java.util.Scanner.nextDouble()方法的聲明
public double nextDouble()
參數
-
NA
返回值
此方法返回從輸入信息掃描的double值
異常
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InputMismatchException -- 如果下一個標記不匹配的浮動正則表達式,或者是超出範圍
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NoSuchElementException -- 如果輸入被耗儘
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IllegalStateException -- 如果此scanner 已關閉
例子
下麵的示例演示java.util.Scanner.nextDouble()方法的用法。
package com.yiibai; import java.util.*; public class ScannerDemo { public static void main(String[] args) { String s = "Hello World! 3 + 3.0 = 6 true"; // create a new scanner with the specified String Object Scanner scanner = new Scanner(s); // use US locale to be able to identify doubles in the string scanner.useLocale(Locale.US); // find the next double token and print it // loop for the whole scanner while (scanner.hasNext()) { // if the next is a double, print found and the double if (scanner.hasNextDouble()) { System.out.println("Found :" + scanner.nextDouble()); } // if a double is not found, print "Not Found" and the token System.out.println("Not Found :" + scanner.next()); } // close the scanner scanner.close(); } }
讓我們來編譯和運行上麵的程序,這將產生以下結果:
Not Found :Hello Not Found :World! Found :3.0 Not Found :+ Found :3.0 Not Found := Found :6.0 Not Found :true