Java.util.ArrayList.contains()方法實例
java.util.ArrayList.contains(Object) 如果此列表包含指定的元素方法返回true。
聲明
以下是java.util.ArrayList.contains()方法的聲明
public boolean contains(Object o)
參數
-
o -- 其存在於該列表用來進行測試的元素。
返回值
如果此列表包含指定的元素,此方法返回true。
異常
-
NA
例子
下麵的示例演示java.util.Arraylist.contains方法的用法。
package com.yiibai; import java.util.ArrayList; public class ArrayListDemo { public static void main(String[] args) { // create an empty array list with an initial capacity ArrayList<Integer> arrlist = new ArrayList<Integer<(8); // use add() method to add elements in the list arrlist.add(20); arrlist.add(25); arrlist.add(10); arrlist.add(15); // let us print all the elements available in list for (Integer number : arrlist) { System.out.println("Number = " + number); } // list contains element 10 boolean retval = arrlist.contains(10); if (retval == true) { System.out.println("element 10 is contained in the list"); } else { System.out.println("element 10 is not contained in the list"); } // list does not contain element 30 boolean retval2 = arrlist.contains(30); if (retval2 == true) { System.out.println("element 30 is contained in the list"); } else { System.out.println("element 30 is not contained in the list"); } } }
讓我們來編譯和運行上麵的程序,這將產生以下結果:
Number = 20 Number = 25 Number = 10 Number = 15 element 10 is contained in the list element 30 is not contained in the list